4c^2-17c+15=0

Solution for 4c^2-17c+15=0 equation:

Simplifying
4c2 + -17c + 15 = 0

Reorder the terms:
15 + -17c + 4c2 = 0

Solving
15 + -17c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + -4c)(3 + -1c) = 0

Subproblem 1
Set the factor '(5 + -4c)' equal to zero and attempt to solve:

Simplifying
5 + -4c = 0

Solving
5 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -4c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -4c = 0 + -5
-4c = 0 + -5

Combine like terms: 0 + -5 = -5
-4c = -5

Divide each side by '-4'.
c = 1.25

Simplifying
c = 1.25
Subproblem 2
Set the factor '(3 + -1c)' equal to zero and attempt to solve:

Simplifying
3 + -1c = 0

Solving
3 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1c = 0 + -3
-1c = 0 + -3

Combine like terms: 0 + -3 = -3
-1c = -3

Divide each side by '-1'.
c = 3

Simplifying
c = 3
Solution
c = {1.25, 3}